X^2+30x-260=0

Solution for X^2+30x-260=0 equation:

X^2+30X-260=0

a = 1; b = 30; c = -260;
Δ = b2-4ac
Δ = 302-4·1·(-260)
Δ = 1940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1940}=\sqrt{4*485}=\sqrt{4}*\sqrt{485}=2\sqrt{485}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{485}}{2*1}=\frac{-30-2\sqrt{485}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{485}}{2*1}=\frac{-30+2\sqrt{485}}{2}
$